java - How to Use Parse.com Lists in Tabs? -

-

मुझे निम्नलिखित फ़ंक्शन मिल गया है: 

  सार्वजनिक स्थिर वर्ग ListFragment टुकड़ा बढ़ाता है {निजी ParseQueryAdapter & LT; ParseObject & gt; mainAdapter; निजी सूचीदृश्य सूची देखें; सार्वजनिक देखें क्रिएटिव्यू (लेआउटइनफ्लेटर इन्फ्लाटर, व्यू ग्रुप कंटेनर, बंडल बचाए गए इन्स्टेंसस्टेट) {देखें रूटव्यू = इन्फ्लिएटर.inफ्लैट (आर। लेट। फ्रैग्मेंट लिस्ट, कंटेनर, फॉल्स); मुख्य एडाप्टर = नया पैरासेक्यूएडएप्टर & lt; पार्स ऑब्जेक्ट & gt; (यह, "टोडो"); mainAdapter.setTextKey ( "शीर्षक"); mainAdapter.setImageKey ( "छवि"); // प्रारंभ सूची सूची देखें और मुख्य एडेप्टर सूची में प्रारंभिक दृश्य सेट करेंदृश्य = (सूची दृश्य) findViewById (R.id.list); listView.setAdapter (mainAdapter); mainAdapter.loadObjects (); वापसी रूट दृश्य; }}   
 त्रुटियों को वापस कर दिया गया है:  
 कन्स्ट्रक्टर पैरासेक्यूएडैप्टर (मेनएक्टिविटी.लिस्टफ्रैग्मेंट, स्ट्रिंग) अपरिभाषित है MainActivity.java  
 गैर-स्थिर विधि के लिए स्थैतिक संदर्भ प्रकार VivById (int) प्रकार की गतिविधि MainActivity.java  
 से मैं मान सकता हूँ कि पहली  इस  प्रकार के ऑब्जेक्ट के परिवर्तन के कारण लेकिन मुझे सही फिक्स पर अधिक अनुभवी इनपुट चाहिए।  
 दूसरी त्रुटि हालांकि अच्छी तरह से उलझा हुआ है क्योंकि यह मेरी आंखों के लिए मान्य है।  
 किसी भी इनपुट की सराहना करते हैं।   
 
 
  1)   ParseQueryAdapter  का तत्काल परिवर्तन निम्न प्रकार से करें। कोड  टुकड़ा  में है, लेकिन  ParseQueryAdapter  को  context  ऑब्जेक्ट की आवश्यकता है।  
  mainAdapter = new ParseQueryAdapter & lt; ParseObject & gt; (this.getActivity (), "Todo");   
 
  2)  अपनी कक्षा परिभाषा से  स्थिर  संशोधक निकालें।

Comments

Post a Comment

Popular posts from this blog

mysql - where clause in inner join query -

-
Please help me about this question: Look for functions ($ userpno) } {Echo $ userpno; $ This-> query = "SELECT task.employee_id, task.user_id, task.service_id, service.name AS servicename, service.description AS servicedescription, employee.name as employineame, employee.pic_path employment, employee.pic_path from work Work.user_id = '$ userpno' Join the INNER employee. Pno = task.employee_id Join INNER user user.pno = task.user_id service.service_id = task.service_id "INNER service; } query works perfectly without: WHERE task.user_id = '$ userpno' my Also try this method: WHERE task.user_id = $ userpno but it does not work. Error: Warning: mysqli_fetch_array () parameter 1 is expected to be mysqli_result, given in Boolean C: \ wamp \ www \ admin \ classes \ Task Php on line 22 Please tell me where I say where is it. Try: $ this-> query = "SELECT Task.employee_id, task.user_id, task.service_id, service.name AS s...
Read more

java - Why my included JSP file won't get processed correctly? -

-
I am trying to create Java web framework (and learning), and on the basis of 'Code Generator In the process of making the material view of the database in the process of development, I stumbled into a difficulty, which I do not know how to solve it. First of all, I want the following index.jsp : & lt; Body & gt; Use all pages to be created. & Lt;% @ include file = "header.jsp"% & gt; & Lt; Hours / & gt; & Lt;% @ included file = "body.jsp"%> & Lt; Hours / & gt; & Lt;% @ include file = "footer.jsp"% & gt; & Lt; / Body & gt; And, in body.jsp , I should have it like this: & lt; Jsp: include page = "$ {Application_modul}"%> Where application_modul is an attribute defined in its controller: request.setAttribute ("application_modul", "USER_ACCOUNT \\ ' View_user_account.jsp "); This file can be found properly, but the processed JSP does ...
Read more

php - MySQL Query for Advanced Search multiple criteria -

-
I am working through an advanced search query where users select the checkbox based on multiple criteria. I am starting because I am hoping that I will know whether I am on the right path. I know that the query is quite messy Edit: I realized that there are two questions to be needed, so I have strictly modified a question question table data tables ss_users user_id FIRST_NAME LAST_NAME admin_level user_approved 1 Nick Jones 0 1 2 Johnny Rocket 0 1 table ss_user_profile_status user_id photo_uploaded 1 1 2 1 table ss_user_photos selected user_id file name photo_id 1 1 photo_1 .jpg 1 2 2 photo_2.jpg 0 3 2 photo_2.jpg 1 table ss_general user_id city state zip neighborhood 1 Baltimore maryland 00125 hamsterdam 2 Lekland My 11542 treemont table ss_languages ​​user_id French German Italian Spanish 1 0 1 0 1 2 0 1 1 Table ss_experience Waldorf Kumon homeschooling user_id 1 0 1 0 2 0 0 1 My current The result is that all users, which should not be the case: ... Select ss_use...
Read more