sql - how to search a word with in a column and split the date followed by the word -

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मेरे पास दो स्तंभ बनाने की तिथि और Rtrail

उदाहरण

बनाएं_डेट ------------------------------------ Rtrail

5/4/2014 6:28:34 PM ...................................... ..मिमिन (05/11/14 20:16:19) - & gt; डीडी (05/11/14 21:17:04)

आउटपुट

बनाएं_डेट ------------------------------------ Rtrail

05/11/14 20:16:19 अपराह्न ........................... ............. अमीन (05/11/14 20:16:19) - & gt; डीडी (05/11/14 21:17:04)

अब मुझे स्प्लिट डेटटाइम चाहिए जो कि "** amin " से शुरू होता है और पिछला कॉलम " दिनांक बनाएं " को अपडेट करें।

यह काम करता है आपके द्वारा प्रदत्त नमूना डेटा पर। इस रूप में यह बहुत भंगुर है मैं कुछ जोड़ूंगा जहां भविष्य के (और) अस्तित्व की जाँच करने के साथ-साथ यह सुनिश्चित करने की भी संभावना है कि अंदर के मान को तिथि के रूप में डाला जा सकता है। मैं उस हिस्से को आप पर निर्भर करता हूं। 

  update # कुछ सेट create_date = SUBSTRING (आरट्रिल, चार्ंडएक्स ('(', आरट्रिल) + 1, चैरिन्डेक्स (')', आरट्रिल) - चार्ंडएक्स ( '(', आरस्ट्रियल) - 1)

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