Java: Changing loop counter value inside the loop -

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इस सवाल का पहले से ही एक उत्तर है: < / P>

  • 6 जवाब

    अगर मेरे पास एक पाश है किसी भी लूप) .. अब के लिए लूप को कह देता है: 

      के लिए (int x = 0; x & lt; 100; x ++)   
     यदि, लूप के पुनरावृत्त के भीतर, मैं कहता हूं:  
      x = 50;   
     क्या लूप की अगली पुनरावृत्ति 50 से जुड़ी होगी? या लूप के भीतर x के मान में कोई परिवर्तन लूप काउंटर को प्रभावित नहीं करता है?   
     
     
     के लिए फिर से लिखना डू-ऑल लूप के रूप में नीचे लूप  
      के लिए (int x = 0; x & lt; 100; x ++) cout & lt; & lt; एक्स एंड एलटी; & lt; ""; int x = 0; करना {cout & lt; & lt; एक्स एंड एलटी; & lt; ""; एक्स ++; } जबकि (x & lt; 100);   
     50 के लिए समान

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