Behavior of scanf() in C++ -

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When I put a string, when scanf () expects float? I thought this would be an exception, but I got infinite loop. Why, and how can I control it?

OK, the code is here 

  int main () {float f; scanf ("% f", & amp; f); Cout & lt; & Lt; "F =" & lt; & Lt; F & LT; & Lt; Endl; Return 0; }    
 
 
  scanf  is much read as much as possible, but it hit the end of that input is turned off or if the input number of unread items do not match the specification account, and if it is quickly stops the numbers specified in the format string , And whatever input does not match, will still be in input buffer for future reading. Example:  
 If you have  int count = scanf ("% f", & amp; nbsp;) and  input "1.23", then  Val  will be  1.23 ,  count  will be  1 , and the input will be consumed.  
 If you have  int count = scanf ("% f" and "val")  and the input is "George", then  val  will be unchanged,  Count  will be  0 , and "Python" will still wait on stdin for another reading usage.  
 You can find out the failure by comparing the  count  the number of things you were trying to read, and if it is too small, then somehow get cured. Or discard the input and error.

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