sorting - Sort one list by the order of another list -

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I need to sort a list according to the second list, but I do not know how this can be done.

For example: I can have a list a : 

  [C, B, G, E]  <[A, B, C, D, E, F, G, B, C, D, E, F, G, ...]   
 (Just as an example, These are not real values)  
 Then, the list should be sorted  a  list is same as the list  b  and so on Sorted:  
  [A, B, E, G]   
  
 Any help would be greatly appreciated.  
 
 If I think, one of the lists lists the sequence relative to all the elements in another list. Ie:  
  & gt; Sort with order [5,1,2,3,4] [1,2,3,4,5,5,4,3,2,1] [5,5,1,1,2,2,3, 3, 4, 4]   
 This piece of code should work:  
  Module sortwhit order where importable data. Map. M Limited as import data. Import Import Data. Ord Sort Wideorder :: Ord A = & gt; [A] - Order list - & gt; [A] - Source list - & gt; [A] Sort with order order = Sort by (compare gore order) where mill orderer = m.fundvith default (-1) k ordermap ordermap = M.fromList (zip order [0 ..])

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