python - Passing matrix in recursive sudoku solver -

-

So I wrote the brutal force Sudoku Solver in a time ago. I thought it would be well in Python, so I can only translate my argument (a function can be held legally on (X, Y) and one that finds all solutions repeatedly.) Everything else (mostly I / O) I was able to replace with one-liners (Hurray for Python).

The problem is, the code does not work. "Sud" is a 9x9 matrix (in the beginning) contains unsolved sudoku, the unknown number is represented by zero.

The program does not seem to change the values ​​stored in "sud", so I'm guessing this problem in which my metrics are defined? In C. I defined "sud" in exterior, how can i do it in python? Or do I need to pass the matrix as an argument in my work?

Sorry, if my problem looks trivial, then I am very new in Python.

Below I have the code: 

  N = 9f = open ('sudoku.txt', 'r') tmp = f.read (). Splitlines () for sud = [[int (x)) in the X (I)] for the TMP [I]] in the range (N)] DIF check (X, Y, W): If I [S] for [S] ] Valve in: ### Check the line X for the Wall Return 1 if I in the range 1 (N)] for [sud [i] [x] Val: ### Column for Call Returns Y 1 xx For the range in the range (ybox, ybox + 3) = = (x / 3) * 3 ybox = int (y / 3) * 3 for the range (xbox, xbox + 3): if val == sud [I] [j]: ### Check box 1 for returning return returns 0 Solution Iarf (x = 0, y = 0): if x == N: y + = 1 x = 0 if y == N: return 1 if sud [y] [x] & gt; 0: Resolve solutions (X + 1, Y) to return to range (1, N + 1): If (x, y, i) is not checked then: sud [y] [x] = i Hull (x + 1, y): print (sud) sud [or] [x] = 0 return 0    
 
 
 <0> (xbox, xbox + 3): for category j (ybox, ybox + 3): if val == sud [i] [j]: # # Check box 1 for returning # val;   
 It seems that if you mix your x and y indexing on the line  if ; In the rest of your code, y comes first and x comes in second place. (Xbox, xbox + 3) for category: i for category (ybox, ybox + 3): if val == revenge [j] [ii]: wal return 1 For the ### check box wipe for the   
, the output grows against the sample grid, which produces the output that appears to be correct.

Comments

Post a Comment

Popular posts from this blog

php - PDO bindParam() fatal error -

-
I am trying to learn PDO, now I have written this small code, but it gives me a serious error: < P> Fatal error: Call a member function at a non-object dot () ... $ con = new mysqli ("127.0.0.1", "root", "", "csvdangercheck"); $ Query = $ con- & gt; ("Id,` var1`, `var2`) values ​​(" id,: var1,: var2) ";); $ query- & gt; bypass pattern (': id', $ id); $ query- & gt; BindParam (': var1', $ VAL1); $ Query- & gt; bindParam (': var2', $ val2); $ Query-> Executed (); I Trying to use print_r ($ con-> errorInfo ()) but Fatal error: Undefined method mysqli :: errorInfo ( ) ... can someone tell me what am I missing? Flaffeh said, you have PDO Missing Mysqy, try it: $ con = new PDO ('mysql: host = 127.0.0.1; dbname = csvdangercheck', 'root', '');
Read more

logging - How can I log both the Request.InputStream and Response.OutputStream traffic in my ASP.NET MVC3 Application for specific Actions? -

-
For a specific set of tasks, I need to log in to the incoming request inputstream as well as outgoing response. is. I am using an ActionFilterAttribute for this and overriding the OnActionExecuted and OnResultExecuted methods. So I'm starting with this idea ... Public category ActionLoggerAttribute: ActionFilterArrbit {Public Override Zero On-Offed Execution (ActionActioned Contact Filter Filter) {base.OnActionAxecuted (FilterContext); HttpRequestBase request = filterContext.HttpContext.Request; // TODO: Log the request. InputStream} Public Override Zero OnResultExecuted (ResultExecutedContext FilterContext) {base.OnResultExecuted (filterContext); HTTPRPSPointBase Response = FilterContacts Hpptex response; // TODO: Log on Response.OutputStream}} Ideally I'll hook it up with enterprise library logging because I'm already using it for error logging. Am I reaching the input and output stream at the right time? Can I easily use the Enterprise Library to log i
Read more

java - Why my included JSP file won't get processed correctly? -

-
I am trying to create Java web framework (and learning), and on the basis of 'Code Generator In the process of making the material view of the database in the process of development, I stumbled into a difficulty, which I do not know how to solve it. First of all, I want the following index.jsp : & lt; Body & gt; Use all pages to be created. & Lt;% @ include file = "header.jsp"% & gt; & Lt; Hours / & gt; & Lt;% @ included file = "body.jsp"%> & Lt; Hours / & gt; & Lt;% @ include file = "footer.jsp"% & gt; & Lt; / Body & gt; And, in body.jsp , I should have it like this: & lt; Jsp: include page = "$ {Application_modul}"%> Where application_modul is an attribute defined in its controller: request.setAttribute ("application_modul", "USER_ACCOUNT \\ ' View_user_account.jsp "); This file can be found properly, but the processed JSP does
Read more