jsonschema - Writing JSON schema to detect objects with duplicate names -

-

निम्न पोस्ट के अनुसार;

उसी नाम के साथ कुंजी JSON मान्य है, लेकिन अधिकांश पार्सर्स उस मान को अंतिम मूल्य के साथ ओवरराइड करेंगे जो इसे पाता है। क्या किसी भी तरह से एक JSON स्कीमा में डुप्लिकेट नाम का पता लगाने और एक त्रुटि फेंकने के लिए? मैं चाहता हूं कि सभी जेसन कुंजियों को एक वस्तु में अद्वितीय नाम मिलें।

जेसन-स्कीमा वैध JSON ऑब्जेक्ट्स के साथ काम करती है , इसलिए डुप्लिकेट कुंजी को रोकने के लिए ऐसा कुछ नहीं है।

मैं आपको JSON-schema validator के साथ मान्य करने से पहले एक जेसनलाइन को पूर्वप्रक्रिया के रूप में उपयोग करने का सुझाव देता हूं। यह आपकी प्रोग्रामिंग भाषा पर निर्भर करेगा लेकिन यहां आपके पास कुछ विकल्प हैं:

  • ।


Comments

Post a Comment

Popular posts from this blog

php - How can I cram 6+31 numeric characters into 22 alphanumeric characters? -

-
I have a 6 digit number and a 31-digit number (such as "234536" and "201103231043330478311223582826") that I The API needs to be crawled in the same 22-character alphanumeric field that uses PHP. I tried to convert each one to 32 (using custom code could not handle the base_convert () large number) and to connect with a single-character delimiter, but It only gives me 26 characters This is a restore API, so the letters should be URI-protected. I would like to do a database table cross with two references without reference to another reference value, if possible, any suggestions? Instead use a radix of 62. This will give you 22 characters for the top, 3.35 for the pre and 17.3 for the next. & gt; & Gt; & Gt; Math.log (10 ** 6) /math.log (62) 3.3474826039165504 & gt; & Gt; & Gt; Math.log (10 ** 31) /math.log (62) 17.295326786902177
Read more

mysql - where clause in inner join query -

-
Please help me about this question: Look for functions ($ userpno) } {Echo $ userpno; $ This-> query = "SELECT task.employee_id, task.user_id, task.service_id, service.name AS servicename, service.description AS servicedescription, employee.name as employineame, employee.pic_path employment, employee.pic_path from work Work.user_id = '$ userpno' Join the INNER employee. Pno = task.employee_id Join INNER user user.pno = task.user_id service.service_id = task.service_id "INNER service; } query works perfectly without: WHERE task.user_id = '$ userpno' my Also try this method: WHERE task.user_id = $ userpno but it does not work. Error: Warning: mysqli_fetch_array () parameter 1 is expected to be mysqli_result, given in Boolean C: \ wamp \ www \ admin \ classes \ Task Php on line 22 Please tell me where I say where is it. Try: $ this-> query = "SELECT Task.employee_id, task.user_id, task.service_id, service.name AS s...
Read more

java - Why my included JSP file won't get processed correctly? -

-
I am trying to create Java web framework (and learning), and on the basis of 'Code Generator In the process of making the material view of the database in the process of development, I stumbled into a difficulty, which I do not know how to solve it. First of all, I want the following index.jsp : & lt; Body & gt; Use all pages to be created. & Lt;% @ include file = "header.jsp"% & gt; & Lt; Hours / & gt; & Lt;% @ included file = "body.jsp"%> & Lt; Hours / & gt; & Lt;% @ include file = "footer.jsp"% & gt; & Lt; / Body & gt; And, in body.jsp , I should have it like this: & lt; Jsp: include page = "$ {Application_modul}"%> Where application_modul is an attribute defined in its controller: request.setAttribute ("application_modul", "USER_ACCOUNT \\ ' View_user_account.jsp "); This file can be found properly, but the processed JSP does ...
Read more