Find last occurrence of any item of one list in another list in python -

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I have the following 2 listings in Python: 
  ll = [500,500,500,501,500,502,500] mm =  
 
 [4 9, 5, 5, 502]  < / pre> 
 In the list, I want to know the position of the last chance of any item. I can do this for one element:  
  lane (ll) - 1 - Ll [:: - 1] Index (502)> gt; & Gt; 5   
 Take here [:: - 1]. Indices (502) 502 provides last position and gives lane -1 total length.  
 How do I extend the entire list to work for mm? I know that I can write a function, but another dragon is the way   
 
 
 if you want  Last  Index   
  Ll =       ll  [500,500,500,501,500,502,500] mm = [49 9, 501502] d = {v: k for calculate in k, v (ll) if v in mm} # {501: 3, 502: 5}   
 Instead of o (n) it is possible to create a  set  to  set  before creating a (1) lookup, but three items For this, it is not really worth following the apro worries about maintaining unavailable index as  any  and make it a  O (1)  lookup Is using a hash lookup for. .  
  # Create a key- gt; Do not have any word for all `mm`d = dict.fromkeys (mm) - com d. For update (k), (v, v) enumerate (ll) if in v = d) # {499: none, 501: 3, 502: 5}

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