c++ - How can I define a function that takes as a parameter a pointer value of any kind? -

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I am implementing a smart pointer class practice.

I have already defined the assignment operator overload, taking one more example of the same class. Now I want to define the surcharge of this operator, which takes any indicator. That's why I got the smartPointer = & amp; SomeObject; or smartPointer = NULL; , etc.

How can I do that? Do I pass in void * ? Some more questions?

As another general question (and I know that it is rarely desired): What type of parameter tells the compiler that any indicators can be passed?

Using a template function to allow you to assign your object to a pointer Can. 

  template & lt; Type name T & gt; Zero operator = (T * oBJ) {// your code here}   
 However, this is not a smart pointer if you can provide it as any raw pointers because it There will be one problem with more than one smart pointer object and then deleting the pointer.

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