Lisp function getting wrong number of arguments -

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इस सवाल का पहले से ही एक उत्तर है: < / P>

  • 4 जवाब

    मैंने निम्नलिखित को परिभाषित किया है फ़ंक्शन soma-n जहां n एक पूर्णांक है और l एक सूची है। 

      (defun soma- एन (एनएल) (यदि (नल एल) () (विपक्ष (+ (प्रथम एल) एन) (सोमा- n (बाकी एल))))   
     मैं कोशिश कर रहा हूँ इसे इस प्रकार कहते हैं, लेकिन ऐसा लगता है कि कोई तर्क नहीं भेजा गया है, क्योंकि मुझे निम्न त्रुटि मिल रही है:  
      (सोम-एन 3 '(1 2 3)); सोमा-एन को 1 एआरजी मिला, कम से कम 2 करना चाहता था।   
     जिस तरह से मैं फ़ंक्शन बुला रहा हूँ उसमें समस्या क्या है?   
     
     
     यह वही है जिसे आप शायद चाहते थे  
      (defun soma-n (nl) (यदि (नल एल) () (विपक्ष)   
     आप कुछ-एन की पुनरावर्ती कॉल की एक सूची गुजर रहे थे

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