html - Make link submit identically to default button behavior -

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Sorry if it seems redundant, I have read through a few posts and can not figure out how to be done. I need an element that behaves like a button, but I thought instead to use a CSS class object. I find out how to do this by creating href = "#" and adding Javascript commands I 

  & lt; P & gt; & Lt; Input name = "test" type = "button" value = "click" /> & Lt; / P & gt;   
 However, due to server side software I am using I need to submit my form to duplicate the behavior of the button exactly.  
 I have been guessed:  
  & lt; P & gt; & Lt; One square = "button" href = "#" onclick = "submit ()" & gt; Click & lt; / A & gt; & Lt; / P & gt;   
 Thank you for your help!   
 
 
 You have the  form  in the context of the element, and then submit:  
  & lt; P & gt; & Lt; A class = "button" href = "#" onclick = "document.getElementById ('myFormId') presented ()" & gt; Click & lt; / A & gt; & Lt; / P & gt;   
 However, you should not use inline event delegation:  
 HTML:  
  & lt; P & gt; & Lt; One class = "button" href = "#" id = "submit-anchor" & gt; Click & lt; / A & gt; & Lt; / P & gt;   
 JS:  
  document.getElementById ("submit-anchor"). addEventListener ("click", function () {document.getElementById ('myFormId'). Submit ();});

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