Compile Python 3.4 with sqlite3 -

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I have compiled SQLite3 3.8.6 and installed it with $ {HOME} / opt: 

  LDFLAGS = "- L $ {HOME} / opt / lib" CFLAGS = "- Include L $ {HOME} / opt /" ./configure --prefix = $ HOME / OPT Make & amp; Install   
 I'm trying to compile Python 3.4.2 to use this version instead of the version for the whole system. I do not have root access on this system. To compile Python, I am using:  
  LDFALGS = "- $ {HOME} / OPT / LIB" CFLAGS = "- L $ {HOME} / opt / included "./configure - -profix = $ HOME / OPT & amp; Amp;   
 I was able to compile Python 3.3.5 with my new version if SQLite3, but this same step does not work for me 3.4.2.  
 How do I compile Python 3.4.2 to include my version of SQLite 3.8.6 which is $ {HOME} / opt?  
 Located in Thanksgiving.  
 Thank you. >  Edit:  It compiles & amp; Except this fact that it is using the old version, instead of version, the system version of sqlite3 which I compiled & amp; Has established itself. 
  
 
 
 There is also the option of adding your custom Python build before sqlite3. (I had the same problem: was using Scratch 3 provided by the custom dragon system, completely ignoring the built-in sqlite3).   
  LD_RUN_PATH = $ HOME / opt / lib configured with your  configure  and  prefix  LDFLAGS = "- $ HOME / opt / lib" CPPFLAGS = "- $ HOME / opt / include" A? ? | LD_RUN_PATH = $ HOME / opt / lib build   
 so that the default  python3  created is linked to your SQLite 3. It worked for me.

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