java - Check if String contains regex match -

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I am working on a program that is an interpreter for a simple language that works with the group and sets Operates. It currently works with the holding numbers set.

When the user defines the set, then the input looks like this: set1 = {1, 25, 5, 6};

such as set1 = {1, 25, 5, 6} can also work, but

do something like this Set1 = {1 25, 5,6}; should not

so basically it does not matter to the empty space, if any "," between numbers it's OK.

What I need to check is what is there in string

between any "," , anywhere After the blank space and the second number, I am doing this: 

  Pattern Pattern = Pattern.compile ("[0-9] [\" \ "] + [0- 9]" ); Matcher matcher = pattern.matcher (input); If (matcher.find ()) false return;   
 And it works just fine. But this is a university assignment and I'm not sure that I have permission to use the  pattern  and  Matcher .  
 So my question is, is there any other way that I can see that there is a regex in any  string ? Or is there any other easy way to get it?  
 
 Since this is an assignment, I will not write code outside, but there is an alternative solution:  
     
  •  ,  Divide the string on the token (using  String.split () )  
  •  Each of the resulting split array For the Member: 
       
    •  Trim the leading and the following empty space from the member  
    •  If the trimmed member is an integer (I will give you  
    •  otherwise: 
         < Li> It is possible to determine For that: 
           
        •  The tokens can meet your criteria (which contain several integers and spaces, but no commas. You have several ways to determine it:  ""  while  loop, or maybe something else. I'll tell you this.

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