php - How Do I Match Square Bracket As A Literal Character Expression? -

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मेरे पास निम्न कोड है: 

  & lt;? Php // $ content = सामग्री के बहुत सारे यहाँ preg_match ('/ टोकन: \' (। *?) \ '/', $ सामग्री, $ टोकन); print_r ($ टोकन); // एक जादू की तरह काम करता है। Preg_match_all ("/ पैरामीटर \ ['एयू' + 'थकी'] = (। *?); /", $ सामग्री, $ मैच 2); print_r ($ match2); // रिक्त सरणी लौटाता है   
 सब कुछ जाँचने के बाद, मैं समाधान के लिए आया था कि बचने में कुछ समस्या है। क्या कोई मेरी मदद कर सकता हैं? मुझे लगता है कि इसके कुछ वर्ग ब्रैकेट्स हैं?  
 पुनश्च: regex के मूल पाठ  परम ['Au' + 'thKey'] = TEXTHERE;    
 
 
 समस्या  +  के साथ है आपको इसे बचने के लिए एक शाब्दिक  +  जैसा  \ +  होना चाहिए या अन्यथा यह पिछले वर्ण को एक या दो बार दोहराएगा।  
  पैराम्स \ ['एयू' \ + 'थाके' \] = (। *?);   
  
 कोड:  
  preg_match_all ("~ params \ ['Au' \ + 'thKey' \] = (। *?); ~ ", $ सामग्री, $ match2);

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