cryptojs - reading encypted object in javascript -

- 

  var टोकन = "WMwiDeJrawUKHif7D5a8yd4ne6Mv"; Var नमक = "ERtrg56hfg5"; Var key = CryptoJS.enc.Hex.parse ('B374A26A71490437AA024E4FADD5B497FDFF1A8EA6FF12F6FB65AF2720B59CCF'); var iv = क्रिप्टोजएस.एन्सी। हेक्स। पार्स ('7 ई892875 ए 52 सी 59 ए 3 बी 588306 बी 13 सी 31 एफबीडी'); var एन्क्रिप्टेड = क्रिप्टोजेश.एएस.एन्सी्रिप्ट (टोकन, कुंजी, {iv: iv}); Context.setVariable ("एन्क्रिप्टेड", एन्क्रिप्टेड);   
 लेकिन यह चर कहा जा रहा है कि यह एक ऑब्जेक्ट है। मुझे क्या करना है   
 
 
 मुझे लगता है कि आपको  encrypted.ciphertext  का उपयोग करना होगा  <पूर्व>  var एन्क्रिप्टेड = क्रिप्टोजेश.एएस.एन्सी्रिप्ट (टोकन, कुंजी, {iv: iv}); Context.setVariable ("एन्क्रिप्टेड टोकन", एन्क्रिप्टेड.सिर्फटेक्स्ट);   
 क्रिप्टोजएस से:  
  एन्क्रिप्शन के बाद आपको वापस मिले सिफरटेक्स्ट अभी तक एक स्ट्रिंग नहीं है । यह एक सिफर पैराम्स ऑब्जेक्ट है एक सिफर पैराम्स ऑब्जेक्ट आपको एन्क्रिप्शन के दौरान उपयोग किए जाने वाले सभी पैरामीटर तक पहुंच देता है। जब आप किसी स्ट्रिंग प्रसंग में एक सिफर पैराम्स ऑब्जेक्ट का उपयोग करते हैं, तो यह प्रारूप स्ट्रैटेजी के अनुसार स्वचालित रूप से एक स्ट्रिंग में परिवर्तित हो जाता है। डिफ़ॉल्ट एक OpenSSL- संगत प्रारूप है।  
  & lt; स्क्रिप्ट & gt; Var एन्क्रिप्टेड = क्रिप्टोजेश.एएस.एन्क्रिप्ट ("संदेश", "गुप्त पासफ्रेज"); चेतावनी (encrypted.key); // 74eb593087a982e2a6f5dded54ecd96d1fd0f3d44a58728cdcd40c55227522223 चेतावनी (एन्क्रिप्टेड.iv); // 7781157e2629b094f0e3dd48c4d786115 चेतावनी (एन्क्रिप्टेड.salt); // 7a25f9132ec6a8b34 चेतावनी (एन्क्रिप्टेड.सिर्फटेक्स्ट); // 73e54154a15d1beeb509d9e12f1e462a0 चेतावनी (एन्क्रिप्टेड); // U2FsdGVkX1 + iX5Ey7GqLND5UFUoV0b7rUJ2eEvHkYqA = & lt; / स्क्रिप्ट & gt;

Comments

Post a Comment

Popular posts from this blog

php - PDO bindParam() fatal error -

-
I am trying to learn PDO, now I have written this small code, but it gives me a serious error: Fatal error: Call a member function at a non-object dot () ... $ con = new mysqli ("127.0.0.1", "root", "", "csvdangercheck"); $ Query = $ con- & gt; ("Id,` var1`, `var2`) values ​​(" id,: var1,: var2) ";); $ query- & gt; bypass pattern (': id', $ id); $ query- & gt; BindParam (': var1', $ VAL1); $ Query- & gt; bindParam (': var2', $ val2); $ Query-> Executed (); I Trying to use print_r ($ con-> errorInfo ()) but Fatal error: Undefined method mysqli :: errorInfo ( ) ... can someone tell me what am I missing? Flaffeh said, you have PDO Missing Mysqy, try it: $ con = new PDO ('mysql: host = 127.0.0.1; dbname = csvdangercheck', 'root', '');
Read more

php - How can I cram 6+31 numeric characters into 22 alphanumeric characters? -

-
I have a 6 digit number and a 31-digit number (such as "234536" and "201103231043330478311223582826") that I The API needs to be crawled in the same 22-character alphanumeric field that uses PHP. I tried to convert each one to 32 (using custom code could not handle the base_convert () large number) and to connect with a single-character delimiter, but It only gives me 26 characters This is a restore API, so the letters should be URI-protected. I would like to do a database table cross with two references without reference to another reference value, if possible, any suggestions? Instead use a radix of 62. This will give you 22 characters for the top, 3.35 for the pre and 17.3 for the next. & gt; & Gt; & Gt; Math.log (10 ** 6) /math.log (62) 3.3474826039165504 & gt; & Gt; & Gt; Math.log (10 ** 31) /math.log (62) 17.295326786902177
Read more

mysql - where clause in inner join query -

-
Please help me about this question: Look for functions ($ userpno) } {Echo $ userpno; $ This-> query = "SELECT task.employee_id, task.user_id, task.service_id, service.name AS servicename, service.description AS servicedescription, employee.name as employineame, employee.pic_path employment, employee.pic_path from work Work.user_id = '$ userpno' Join the INNER employee. Pno = task.employee_id Join INNER user user.pno = task.user_id service.service_id = task.service_id "INNER service; } query works perfectly without: WHERE task.user_id = '$ userpno' my Also try this method: WHERE task.user_id = $ userpno but it does not work. Error: Warning: mysqli_fetch_array () parameter 1 is expected to be mysqli_result, given in Boolean C: \ wamp \ www \ admin \ classes \ Task Php on line 22 Please tell me where I say where is it. Try: $ this-> query = "SELECT Task.employee_id, task.user_id, task.service_id, service.name AS s...
Read more