python - Open / Edit / Save record in Django Form -

-

Currently I have a Django form where I can add a new customer to the database. I currently have a table showing all the customers present in this database. Now I would like to click on the customer's name in the Customer table so that the existing customer can open and have the option to edit and save the record.

Below are my current code sections, if more important, please ask.

My navbar.html 

  & lt; Li & gt; & Lt; A href = '%} "with customer'%} 'customer with {% url} New customer & lt; / A & gt; & Lt; / li & gt;   
 my urls.py  
  url (r '^ customeradd / $', 'customer.views.customeradd', name = 'customeradd'),   
 My views.py  
  def customer application (request): form = CustomerAddForm (request.POST or none) if request.method == 'POST ': If form.is_valid (): save_it = form.save (commit = false) save_it.save () messages.success (request,' customer has successfully added ') HttpResponseRirectirect (' / customeroverview / ') Other: messages Error () request, 'customer save error, please check the field below') Other: form = CustomerAddForm () return to render_to_response ("customer-add.html", {"customer_add_form": form}, context_instance = RequestContext (request))   
 customeroverview.html which shows the table of all customers (only three fields are shown)  
  & lt; Td> & Lt; A href = '{% url' customeradd "%} '& gt; {{customer.customer_name}} & lt; / a & gt; & lt; / td & gt; & lt; td & gt; {{customer. Customer_type}}  & lt; td & gt; {{customer.customer_address}} & lt; / td>   
 So now I'm in the Customer Table Customers can click on the name of the customer and the customer will open the adform. In the current situation, the offers are not empty because no argument is given.  
     
  1.  
     customer.viewer.html at customer How do I give the customer.id field as argument when clicking on the customer_name hyperlink?   
  2.  
     I will give this c How to see the ID. - How should urls.py look like?   
  3.  
     When the form is opened with an existing customer, how do I create a new customer? I save the existing record instead. ID    
     Any help / suggestion on this situation would be very useful in my understanding of Django GET / POST.   
     
     
     Maybe you should:  
     urls.py  url (r '^ Customeradd / (' P & LT; ID & gt; \ W +) $ ',' customer.views.customeradd ', name =' customeredit '), url (r' ^ customeradd / $ ',' customer.views.customeradd ', name =' customer adid '),   
     In your view.py:  def customeradd (request, id = none): If ID: Customer = Customer.Bejects (Pk = id) other customer = no form = customer application (request.post, example = customer) .....   
     in your template  
      & lt; Td> & Lt; A href = '{url url}' Customer customer.ID%} '& gt; {{Customer.customer_name}} & lt; / A & gt; & Lt; / Td> & Lt; Td> {{Customer.customer_type}} & lt; / Td> & Lt; Td> {{Customer.customer_address}} & lt; / Td>

Comments

Post a Comment

Popular posts from this blog

php - PDO bindParam() fatal error -

-
I am trying to learn PDO, now I have written this small code, but it gives me a serious error: < P> Fatal error: Call a member function at a non-object dot () ... $ con = new mysqli ("127.0.0.1", "root", "", "csvdangercheck"); $ Query = $ con- & gt; ("Id,` var1`, `var2`) values ​​(" id,: var1,: var2) ";); $ query- & gt; bypass pattern (': id', $ id); $ query- & gt; BindParam (': var1', $ VAL1); $ Query- & gt; bindParam (': var2', $ val2); $ Query-> Executed (); I Trying to use print_r ($ con-> errorInfo ()) but Fatal error: Undefined method mysqli :: errorInfo ( ) ... can someone tell me what am I missing? Flaffeh said, you have PDO Missing Mysqy, try it: $ con = new PDO ('mysql: host = 127.0.0.1; dbname = csvdangercheck', 'root', '');
Read more

logging - How can I log both the Request.InputStream and Response.OutputStream traffic in my ASP.NET MVC3 Application for specific Actions? -

-
For a specific set of tasks, I need to log in to the incoming request inputstream as well as outgoing response. is. I am using an ActionFilterAttribute for this and overriding the OnActionExecuted and OnResultExecuted methods. So I'm starting with this idea ... Public category ActionLoggerAttribute: ActionFilterArrbit {Public Override Zero On-Offed Execution (ActionActioned Contact Filter Filter) {base.OnActionAxecuted (FilterContext); HttpRequestBase request = filterContext.HttpContext.Request; // TODO: Log the request. InputStream} Public Override Zero OnResultExecuted (ResultExecutedContext FilterContext) {base.OnResultExecuted (filterContext); HTTPRPSPointBase Response = FilterContacts Hpptex response; // TODO: Log on Response.OutputStream}} Ideally I'll hook it up with enterprise library logging because I'm already using it for error logging. Am I reaching the input and output stream at the right time? Can I easily use the Enterprise Library to log i
Read more

java - Why my included JSP file won't get processed correctly? -

-
I am trying to create Java web framework (and learning), and on the basis of 'Code Generator In the process of making the material view of the database in the process of development, I stumbled into a difficulty, which I do not know how to solve it. First of all, I want the following index.jsp : & lt; Body & gt; Use all pages to be created. & Lt;% @ include file = "header.jsp"% & gt; & Lt; Hours / & gt; & Lt;% @ included file = "body.jsp"%> & Lt; Hours / & gt; & Lt;% @ include file = "footer.jsp"% & gt; & Lt; / Body & gt; And, in body.jsp , I should have it like this: & lt; Jsp: include page = "$ {Application_modul}"%> Where application_modul is an attribute defined in its controller: request.setAttribute ("application_modul", "USER_ACCOUNT \\ ' View_user_account.jsp "); This file can be found properly, but the processed JSP does
Read more