scala pattern mathing. What is this matching now -

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  / ** (**) Continuous duplicate pack of list elements in sub-listists. If there are repeated elements in a list then they should be kept in separate Upanishads. Example: Scala & gt; Pack (list ('a,' a, 'a,' a, b, c, c, a, a, d, ee, ee, e)) res0: list [list [symbol]] = list (list List ('A', 'A', List 'D'), List ('E', 'A', 'A', 'A', A), List ('B'), List ('C', C) E, 'E,' E)) * /   
 For the general case of this type:  
  object matchTest1 application {def matchTest (x: int ) Expands: string = x match {case 1 = & gt; "One" case 2 = & gt; "Two" case _ = & gt; "Many"} println (matchTest (3))}   
 I know that it is trying to match  x  with pattern.  
 But as an example below, what is it getting? Resolve similar to  
  // 1- My solution / ** * recursive P8 solution * / def pack (Input: list [any]): [list [any]] = { Diff Comp (L: List [Anyone], Last: Any: Last List: List [Anyone]): List [List [Any]] = {l Match {Case Neil = & gt; List [list [any]] (final list) case head :: tail if head == finalem => COMP (tail, head, head :: last list) case head :: tail if previous list == blue = gt; COMP (Tail, Head, Head :: Nil) Case Head :: Tail = & gt; LastList :: comp (tail, head, head :: zero)}} comp (input, zero, zero)}   
 thanks   
 
 
 This checks  list [any]  for:  
  // Is it a List below? Case Neil = & gt; ... // Is it not empty and the first thing (head) does the 'last Eelam' equal? Case head :: tail if head == last eel => ... // Is it not empty but the final list is empty? Case head :: tail if previous list == blue = gt; ... // head in every case case: tail = & gt;   
 Typically  head :: tail  mails in the list  head  (first object) and a  tail The  tail  should be an empty list, the  tail  can be an empty list, it means  [1]  and < Code> [1, 2]  will be from both  head :: tail , while [] match  zero  only.

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